nth terms
@aajugdar
wut is the question mam ? :)
@lovelyharmonics what???
Find an equation for the nth term of a geometric sequence where the second and fifth terms are -24 and 1536, respectively.
okay the 2nd term is -24 and 5th term is 1536 you have to find the ratio
hmm
no need of of options....see apply nth term = a*(r)^(n - 1)...here u r having n = 2 & 5...make the equations and divide them u will get the common ratio
well you would be multiplying by a negative.... so that makes it either 6 • (-4)^n + 1 or 6 • (-4)^n - 1
for n = 2 the term is -24 and for n = 5 the term is 1536
correct
Substitute 21 for a2 and 567 for a5 in the formula an+=+a1%2A+r%5E%28n-1%29 a2=+a1%2A+r%5E%282-1%29...-> ..a1%2Ar=21 a5=+a1%2A+r%5E%285-1%29...->..+a1%2Ar%5E4=567 Substitute this expression for a1 in the second equation and solve for r. a1+=21%2Fr a1%2Ar%5E4=567 %2821%2Fr%29%2Ar%5E4=567 21%2Ar%5E3=567 r%5E3=567%2F21 r%5E3=27 r=3 Substitute for r in the first equation and solve for a1. a1%2A+r=21 a1%2A3=21 a1+=21%2F3 a1+=7 Now use the formula to find the nth term an. highlight%28an=+7%2A3%5E%28n-1%29%29
copy paste <3
lol
u will get two equations -24 = a*(r)^1 1536 = a*(r)^3....solve these for r
r^4 * 5th term
o a bit mistake
its supposed to be 1536 = a*(r)^4
solve it now 1536/-24 = r^3 r^3 = 64 so r = -4
okay .-. how did you just get ^3 out of ^4..... and where did -24 come from?
isnt 2nd term -24
divide the two equations
r^4/r = r^3
now you hv to find the first term
-24 = a* (-4) so a = 5
oh my god.... math /).(\
now as for nth term Xn = 5(-4)^n-1 thats the equation
no its not .-.
@aajugdar bro it supposed to be a = 6
oh its 6 ^^
yeah my bad
so answer is D
yeah c: one of the two original ones i said earlier c:
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