Question

Question based on Quadratics

Answer 1

If roots of the equation x^2 − 10cx − 11d = 0 are a, b and those of
x^2 − 10ax − 11b = 0 are c, d, then the value of
a + b + c + d is (a, b, c and d are distinct numbers)

Answer 2

Done half of the work , need help ahead

Answer 3

I found ac , b+d

Answer 4

\[\huge ac=121\]
\[\huge b+d = 9(a+c)\]

Answer 5

yeah so far looks good

Answer 6

also u can write
\[a^2-10ac-11d=0\]
and
\[c^2-10ac-11b=0\]
right?

Answer 7

How ?

Answer 8

because a and b are roots of that equation

Answer 9

ok??

Answer 10

Oh dude yes, then probably add them up and solve them

Answer 11

It did't strike me -_-

Answer 12

yeah add them up
\[a^2+c^2-20ac-11(b+d)=0\]
\[(a+c)^2-22*121-99(a+c)=0\]
so a+c=121 0r -22

Answer 13

1210
-22 is not taken

Answer 14

b+d we already know

Answer 15

Nice!

Answer 16

a+b+c+D = 1210

Answer 17

but for a+c=-22 im getting a=c so this value is not possible so
a+b+c+d=1210
ur correct ^_^

Answer 18

Nice problem
All were variables and the answer was number surprising
Beauty of mathematics

Answer 19

;)

Answer 20

good to see ur enjoying :)