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Mathematics 26 Online
OpenStudy (anonymous):

Graph the ordered pairs (4,-2) and (1, -1) and connect to form a line. Which quadrant contains no point for this linear function? Explain how you found your answer.

OpenStudy (anonymous):

Ok, so for this problem, the best thing to do is to graph it out. Graph the points on a graph, and connect them. Do you have graphing paper?

OpenStudy (anonymous):

no sir

OpenStudy (anonymous):

Darn. Ok, the next best thing to do then is to draw your own graph. Can you do that? (with the x-line, y-line, the number lines, all that jazz).

OpenStudy (anonymous):

Bro just explain how you get the answer :)

OpenStudy (anonymous):

Well, this is part of the explanation. You need to plot the points, and draw the line to see what quadrant the line does not fall into.

OpenStudy (anonymous):

just try your best :) to explain to find the answer

OpenStudy (anonymous):

That is how you find it. Look, this really isn't going to make any sense unless you draw it out. It's doubly important because you also have to explain how you found your answer. "Graph the ordered pairs (4,-2) and (1, -1) and connect to form a line. Which quadrant contains no point for this linear function? Explain how you found your answer. " So unless you can visualize it in your head, you need to draw it out.

OpenStudy (anonymous):

found this wont this help? http://mathbits.com/MathBits/StudentResources/GraphPaper/10x10.gif

OpenStudy (anonymous):

Yes, that's perfect. If you can print it out to draw on it would be great, but it's fine just the way it is too. Can you plot the two points on this graph?

OpenStudy (anonymous):

ok i got both on quadrant 5

OpenStudy (anonymous):

lol sorry mean quadrant 4

OpenStudy (anonymous):

Ok, good. Now get a straightedge of some sort, and connect the points on one line. What quadrants does the line land on?

OpenStudy (anonymous):

it lands on 2,3,4

OpenStudy (anonymous):

so the answer is quadrant 1

OpenStudy (anonymous):

Exactly! Now all you have to do is explain how you found it, and you're done :)

OpenStudy (anonymous):

thanks bro :)

OpenStudy (anonymous):

You're welcome. Good job, too!

OpenStudy (anonymous):

thx

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