A right triangle has base (x - 6) units and height (6x - 12) units.

Part A: What is the square of the length of the hypotenuse of the triangle? Show your work. (4 points)

Part B: What is the area of the triangle? (3 points)

Part C: Using the solution obtained in Part B, explain the closure property of multiplication of polynomials. (3 points)

Question

A right triangle has base (x - 6) units and height (6x - 12) units.

Part A: What is the square of the length of the hypotenuse of the triangle? Show your work. (4 points)

Part B: What is the area of the triangle? (3 points)

Part C: Using the solution obtained in Part B, explain the closure property of multiplication of polynomials. (3 points)

anonymous · Answer

that would be 
$$(x-6)^2+(6x-12)^2$$ for the square of the length of the hypotenuse, since via pythagoras 
$$a^2+b^2=c^2$$

anonymous · Answer

ok

anonymous · Answer

What is B

jdoe0001 · Answer

$\bf \textit{area of a triangle}=\cfrac{1}{2}\cdot base\cdot height$

anonymous · Answer

I dont know the answer

jdoe0001 · Answer

well, you have the base, and the height, so, is all you need

jdoe0001 · Answer

"A right triangle has base $\bf (x - 6)$ units and height $\bf (6x - 12)$ units."

anonymous · Answer

ok