A circle is represented by the equation below: (x + 8)2 + (y − 3)2 = 100 Which statement is true? The circle is centered at (−8, 3) and has a radius of 20. The circle is centered at (8, −3) and has a diameter of 20. The circle is centered at (8, −3) and has a radius of 20. The circle is centered at (−8, 3) and has a diameter of 20.
\(\large (x-h)^2+(y-k)^2=r^2 \), is the equation of a circle whose RADIUS is r, and center (h, k) according to the equation you gave, what's your radius? what's your center?
I think that the answer is C because of one pair of (x + 8)2 being positive and (y − 3)2 being negative. @dpaInc
no.... C says the radius is 20... it's not 20
so would it be the diameter is 20 and the radius is 10? therefore making it B?
the diameter is 20.... look at your equation carefully.... what's the center?
I see the +8 and -3 so i thought it was those... do they switch because of the squaring?
no, not because of the squaring... the equation have to written in standard form (with minus signs): \(\large (x+8)^2+(y-3)^2=100 \) \(\large (x--8)^2+(y-3)^2=10^2 \) \(\large (x-(\color{red} {-8}))^2+(y-(\color{red}3))^2=(\color{red}{10})^2 \) so that's how you get the center...
So the center is (8,-3) correct? with a diameter of 20?
it's in RED... center is (-8, 3) with a diameter of 20
oh. i saw the double negative so i thought it became a positive
just remember, if it's written with a plus sign, you need to write it with a minus like: \(\large (x+8)^2=(x--8)^2 \) so h=-8 in this case
ok thank you :) i may have a few more questions and you explain them very well can i tag you in them when i get to them?
yep... no problem...
thx
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