Where do perpendicular bisectors intersect the intercepted arcs?
and also . ... Suppose you have a circle with two chords that are not congruent. Is the shorter chord farther from the center or closer to the center than the longer chord?
@wio @gaberdeen can you help ? please.
Ok, I'll try to help as best as I can. I'll start with the first question. I'm assuming the intercepted arcs look like this. (bad drawing, I know). Is this what you mean so far?
Yes .
Ok. For this problem, do they mean that the perpendicular bisector is just bisecting a line? If yes, then according to what I know, the bisector intersects where those two arcs/circles meet.
Does it have a name like central bisecting or something. im sorry i am in a rush and trying to get this stuff done within the next 4 hours.
It's ok! However, I don't think there is a name for it . . . Do they want a written answer, or can you just label a drawing? I guess you could say they intercept the intercepted arcs in two places, but that might not be correct.
As for the chords question, unfortunately I am currently learning about them myself, so I don't think I can accurately help you there. The way I'm learning about chord functions is pretty different than what you're learning about them, it seems.
However common sense says that (if the center is the origin of a graph) that the shorter chord would be closer. I don't know if that helps at all . . .
Thank for all your help !
You're welcome. And good luck!
|dw:1402703589259:dw| It can be shown that O1O2 bisects AB, as well as arcs ACB and ADB. The name for a line which passes through the mid point of another and is perpendicular to it is called a perpendicular bisector. For example, in the given example, O1O2 is the perpendicular bisector of line segment AB.
Thank you (:
You're welcome!
could you help a few more ?
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