Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

I AWARD METALS!!!!! I have a 69 in Algebra and need someone to help me pass this assignment with a C or higher please!!! I will paste the questions and tell you what I think the answers are

OpenStudy (anonymous):

@mathmale can you help me with this please?

OpenStudy (mathmale):

Hello, Klor, If you'd post one question at a time and type in whatever you have done towards solving it, I'd be happy to give you feedback and guidance.

OpenStudy (anonymous):

me too

OpenStudy (anonymous):

okay! Thank you!

OpenStudy (amtran_bus):

Mathmale is a good help. Especially with limits :)

OpenStudy (anonymous):

This is the first one: A biologist is comparing the growth of a population of flies per week to the number of flies a bullfrog will consume per week. She has devised an equation to solve for which day (x) the bullfrog would be able to eat the entire population. The equation is 2x = 3x - 1. However, she has observed that the bullfrog cannot eat more than seven flies in one week. Explain to the biologist how she can solve this on a graph using a system of equations. Identify any possible constraints to the situation.

OpenStudy (anonymous):

I am not sure how she can solve this on a graph or what the question means by constraints

OpenStudy (anonymous):

@mathmale has helped me before @AmTran_Bus :) He is a great help, I agree!

OpenStudy (triciaal):

can you verify the equation

OpenStudy (anonymous):

What is up there is all they gave me. I guess the actual question though in simpler terms would be "how can the biologist solve this on a graph using a system of equations?"

OpenStudy (anonymous):

Can either of you help me with this?

OpenStudy (mathmale):

I've seen this problem before, and remember that even I had problems interpreting what's being asked for. Unless you MUST do your math homework problems in a certain order, I'd suggest you move on to the next problem, and then the next, and so on, and come back to this current problem if and when you have time.

OpenStudy (anonymous):

Okay. I will. But I can't answer it if I don't know how too :(

OpenStudy (triciaal):

The equation is 2x = 3x - 1. are you sure its not 2x^2 otherwise you have sorry my mistake x=1

OpenStudy (anonymous):

oh yeah sorry it is 2^x = 3x - 1

OpenStudy (anonymous):

Okay so I think I know maybe how you could graph it. By putting it into 2 equations. Like y = 2^x and y = 3x - 1

OpenStudy (anonymous):

and then when you graph them, you get 2 point of intersection.

OpenStudy (anonymous):

and then my restrictions could possibly be since "x" represents number of days, x must be a positive integer. and the y being the number of flies, y also need to be a positive integer

OpenStudy (anonymous):

Just a guess though. Does that sound right or no?

OpenStudy (triciaal):

total flies/ 7 flies per week gives the number of weeks it would take to consume the entire population of flies and the total number of flies is the values of y.

OpenStudy (anonymous):

just substitute y

OpenStudy (anonymous):

okay

OpenStudy (triciaal):

7 is the max no. of flies eaten per week so if this bullfrog ate less than the max allowed per day it would take longer to wipe out the population of flies

OpenStudy (anonymous):

okay. So is my answer wrong?

OpenStudy (anonymous):

ya

OpenStudy (anonymous):

okay.

OpenStudy (anonymous):

try again

OpenStudy (anonymous):

So would my graphing part be wrong too?

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

ugh okay so can you explain this to me then?

OpenStudy (anonymous):

@triciaal already did

OpenStudy (triciaal):

I think your method is fine.

OpenStudy (anonymous):

okay so I'm good on this one?

OpenStudy (triciaal):

I think so. Just remember to include the constraints and limits

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!