How many moles of oxygen gas are needed to react completely with 17.9 mL Mg, with a density of 1.74 g/mL?
unbalanced equation: Mg + O2 “yields”/ MgO
0.212 mol O2
0.641 mol O2
1.28 mol O2
2.56 mol O2
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OpenStudy (lena772):
2Mg + O2 -> 2MgO
mathslover (mathslover):
`\(Mg + O_2 \rightarrow 2MgO\)` = \(Mg + O_2 \rightarrow 2MgO\)
Have you tried anything yet?
OpenStudy (anonymous):
Yeah balancing the equation is the first step
OpenStudy (lena772):
I balanced the equation. I'm assuming I find the volume by dividing the mass by the density?
mathslover (mathslover):
You are given with volume and density
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mathslover (mathslover):
You have to find the mass first.
OpenStudy (lena772):
Well do I have to find the mass?
OpenStudy (lena772):
ok.
mathslover (mathslover):
\(mass = density ~ * Volume \)
Yes, you do have to find the mass. Let me give the rason for that.
OpenStudy (anonymous):
17.9 x 1.74 gram Mg = 31.15 gram Mg
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OpenStudy (lena772):
gram Mg what type of unit is that...?
mathslover (mathslover):
*reason.
You have : \(2Mg + O_2 \rightarrow 2 Mg O\)
Now, 2 moles of Mg react with 1 moles of Oxygen gas ( O_2) to form 2 moles of MgO
So, if you will find the number of moles of Mg required, then you can easily find the required moles of O_2
OpenStudy (lena772):
okay.
mathslover (mathslover):
gram Mg means gram of magnesium.
OpenStudy (lena772):
Okay.
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mathslover (mathslover):
So, now, what we have is :
Density (unit is gram per mL ) = ?
Volume (unit is mL ) = ?
OpenStudy (lena772):
1.74 g/mL
OpenStudy (lena772):
17.9 mL Mg
mathslover (mathslover):
right! now, find the mass using mass = volume * desnity
mathslover (mathslover):
*density (typo)
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OpenStudy (lena772):
31.15 g Mg
mathslover (mathslover):
Right. So, now, we need to find the number of moles of Mg :
Number of moles = Given mass / Molar mass
What is the atomic mass of Magnesium (Mg) ?
OpenStudy (lena772):
24.31
OpenStudy (lena772):
g
mathslover (mathslover):
Good! So, find the number of moles now.
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OpenStudy (lena772):
1.281
OpenStudy (lena772):
mol
OpenStudy (lena772):
so C?
OpenStudy (anonymous):
-_-
OpenStudy (lena772):
what's wrong @No.name
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mathslover (mathslover):
Correct, now, see :
2 moles of Mg react with 1 moles of Oxygen gas to yield 1 mole of MgO
i.e. 2 * moles of Mg should be equal to 1 mole of oxygen
OpenStudy (anonymous):
Let @mathslover explain
mathslover (mathslover):
That correct was for "no. of moles =1.281 "
OpenStudy (lena772):
So it's D? 1.28 * 2 =2.56
mathslover (mathslover):
Oops wait..
2 moles of Mg react with 1 moles of Oxygen gas to yield 1 mole of MgO
i.e. 2 * moles of Mg should be equal to 1 mole of oxygen
This was wrongly phrased. Wait please.
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OpenStudy (lena772):
Nah, I'm just dumb IG...
OpenStudy (lena772):
@No.name seems to think so too
OpenStudy (anonymous):
no u r smart
OpenStudy (lena772):
hmm
mathslover (mathslover):
what we found is 1.28 moles of Mg which is actuall equal to 2 *moles of Mg
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OpenStudy (lena772):
well, thanks
OpenStudy (lena772):
so divide by 2 and get 0.64
mathslover (mathslover):
Right!
OpenStudy (lena772):
yay
OpenStudy (lena772):
Thanks @mathslover
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