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Chemistry 7 Online
OpenStudy (lena772):

How many moles of oxygen gas are needed to react completely with 17.9 mL Mg, with a density of 1.74 g/mL? unbalanced equation: Mg + O2 “yields”/ MgO 0.212 mol O2 0.641 mol O2 1.28 mol O2 2.56 mol O2

OpenStudy (lena772):

2Mg + O2 -> 2MgO

mathslover (mathslover):

`\(Mg + O_2 \rightarrow 2MgO\)` = \(Mg + O_2 \rightarrow 2MgO\) Have you tried anything yet?

OpenStudy (anonymous):

Yeah balancing the equation is the first step

OpenStudy (lena772):

I balanced the equation. I'm assuming I find the volume by dividing the mass by the density?

mathslover (mathslover):

You are given with volume and density

mathslover (mathslover):

You have to find the mass first.

OpenStudy (lena772):

Well do I have to find the mass?

OpenStudy (lena772):

ok.

mathslover (mathslover):

\(mass = density ~ * Volume \) Yes, you do have to find the mass. Let me give the rason for that.

OpenStudy (anonymous):

17.9 x 1.74 gram Mg = 31.15 gram Mg

OpenStudy (lena772):

gram Mg what type of unit is that...?

mathslover (mathslover):

*reason. You have : \(2Mg + O_2 \rightarrow 2 Mg O\) Now, 2 moles of Mg react with 1 moles of Oxygen gas ( O_2) to form 2 moles of MgO So, if you will find the number of moles of Mg required, then you can easily find the required moles of O_2

OpenStudy (lena772):

okay.

mathslover (mathslover):

gram Mg means gram of magnesium.

OpenStudy (lena772):

Okay.

mathslover (mathslover):

So, now, what we have is : Density (unit is gram per mL ) = ? Volume (unit is mL ) = ?

OpenStudy (lena772):

1.74 g/mL

OpenStudy (lena772):

17.9 mL Mg

mathslover (mathslover):

right! now, find the mass using mass = volume * desnity

mathslover (mathslover):

*density (typo)

OpenStudy (lena772):

31.15 g Mg

mathslover (mathslover):

Right. So, now, we need to find the number of moles of Mg : Number of moles = Given mass / Molar mass What is the atomic mass of Magnesium (Mg) ?

OpenStudy (lena772):

24.31

OpenStudy (lena772):

g

mathslover (mathslover):

Good! So, find the number of moles now.

OpenStudy (lena772):

1.281

OpenStudy (lena772):

mol

OpenStudy (lena772):

so C?

OpenStudy (anonymous):

-_-

OpenStudy (lena772):

what's wrong @No.name

mathslover (mathslover):

Correct, now, see : 2 moles of Mg react with 1 moles of Oxygen gas to yield 1 mole of MgO i.e. 2 * moles of Mg should be equal to 1 mole of oxygen

OpenStudy (anonymous):

Let @mathslover explain

mathslover (mathslover):

That correct was for "no. of moles =1.281 "

OpenStudy (lena772):

So it's D? 1.28 * 2 =2.56

mathslover (mathslover):

Oops wait.. 2 moles of Mg react with 1 moles of Oxygen gas to yield 1 mole of MgO i.e. 2 * moles of Mg should be equal to 1 mole of oxygen This was wrongly phrased. Wait please.

OpenStudy (lena772):

Nah, I'm just dumb IG...

OpenStudy (lena772):

@No.name seems to think so too

OpenStudy (anonymous):

no u r smart

OpenStudy (lena772):

hmm

mathslover (mathslover):

what we found is 1.28 moles of Mg which is actuall equal to 2 *moles of Mg

OpenStudy (lena772):

well, thanks

OpenStudy (lena772):

so divide by 2 and get 0.64

mathslover (mathslover):

Right!

OpenStudy (lena772):

yay

OpenStudy (lena772):

Thanks @mathslover

OpenStudy (lena772):

and @No.name

mathslover (mathslover):

You're welcome @Lena772 ! Good Luck.

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