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Chemistry 14 Online
OpenStudy (anonymous):

if 1 mole = 10000 millimoles (abbr : Mmol). If 53g Na2CO3 put into a volumetric flask of 250ml, the molarity of this solution is?

OpenStudy (abhisar):

Hello @dinisha !

OpenStudy (abhisar):

Molarity = moles of solute/volume of solution

OpenStudy (abhisar):

So first we will have to calculate the no of moles in 53g Na2CO3

OpenStudy (abhisar):

Can u do tha ?

OpenStudy (anonymous):

ya i gt o.5 mol

OpenStudy (abhisar):

Now divide it with the volume given

OpenStudy (abhisar):

dont forget to convert it into L first

OpenStudy (anonymous):

250ml = 0.25L molarity = 0.5/0.25 = 2.00M

OpenStudy (abhisar):

Bingo !!

OpenStudy (anonymous):

and can i know the formula for normality??

OpenStudy (abhisar):

The normality of a solution is the gram equivalent weight of a solute per liter of solution.

OpenStudy (abhisar):

u know gram equivalent ?

OpenStudy (anonymous):

no sorry

OpenStudy (abhisar):

okay lets work out an example

OpenStudy (abhisar):

u clear with this one ??

OpenStudy (anonymous):

i have a question here can i write out?

OpenStudy (abhisar):

related to this one ??

OpenStudy (anonymous):

normality

OpenStudy (abhisar):

yes post it as a new one

OpenStudy (anonymous):

yes thank you

OpenStudy (abhisar):

\(\Huge\text{Anytime !}\) \(\huge\ddot\smile\)

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