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OpenStudy (anonymous):
if 1 mole = 10000 millimoles (abbr : Mmol). If 53g Na2CO3 put into a volumetric flask of 250ml, the molarity of this solution is?
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OpenStudy (abhisar):
Hello @dinisha !
OpenStudy (abhisar):
Molarity = moles of solute/volume of solution
OpenStudy (abhisar):
So first we will have to calculate the no of moles in 53g Na2CO3
OpenStudy (abhisar):
Can u do tha ?
OpenStudy (anonymous):
ya i gt o.5 mol
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OpenStudy (abhisar):
Now divide it with the volume given
OpenStudy (abhisar):
dont forget to convert it into L first
OpenStudy (anonymous):
250ml = 0.25L
molarity = 0.5/0.25 = 2.00M
OpenStudy (abhisar):
Bingo !!
OpenStudy (anonymous):
and can i know the formula for normality??
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OpenStudy (abhisar):
The normality of a solution is the gram equivalent weight of a solute per liter of solution.
OpenStudy (abhisar):
u know gram equivalent ?
OpenStudy (anonymous):
no sorry
OpenStudy (abhisar):
okay lets work out an example
OpenStudy (abhisar):
u clear with this one ??
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OpenStudy (anonymous):
i have a question here can i write out?
OpenStudy (abhisar):
related to this one ??
OpenStudy (anonymous):
normality
OpenStudy (abhisar):
yes post it as a new one
OpenStudy (anonymous):
yes thank you
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OpenStudy (abhisar):
\(\Huge\text{Anytime !}\)
\(\huge\ddot\smile\)
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