if 1 equivalent = 10000 milliequivalent (abbr : meq). If 53g Na2CO3 put into a volumetric flask of 250ml, dissolved by adding water until the linemark. the normality of this solution is?

Question

abhisar · Answer

okay lets first calculate equivalent mass of Na2CO3

abhisar · Answer

I think u knw that Na2CO3 is a salt ?

anonymous · Answer

yaa i know

abhisar · Answer

okay that's great !
Now equivalent weighgt for salt = Molecular weight/Total charge on cation/anion

abhisar · Answer

Here total charge on cation or anion is 2

abhisar · Answer

and we just calculated the molecular weight i.e 106

abhisar · Answer

so eq wt = 53

abhisar · Answer

got it ?

anonymous · Answer

ya i understand!!

abhisar · Answer

now the next step is to calculate the equivalents of Na2CO3 in 53g Na2CO3

abhisar · Answer

It will be mass of solute/ equivalent mass=53/53=1

abhisar · Answer

Final step will be Normality = equivalents/volume(L)= (1X1000)/250 = 4

anonymous · Answer

perfect thank u soo much!! i really understand to the bit :)

abhisar · Answer

$\Huge\text{Anytime !}$
$\huge\ddot\smile$