Question

366 players participate in a knock-out tournament. In each round all competing players pair together and play a match, the winner of each match moving to the next round. If at the end of a round there is an odd number of winners, the unpaired one moves to the next round without playing a match. What is the total number of matches played?

Answer 1

help: @hartnn

Answer 2

@Miracrown

Answer 3

i think i got it myself..
i got 365, if i'm wrong then tell me

Answer 4

So tentatively, I believe this is as simple as finding the first power of two, which is greater than 366. So 2^9, but let's just think it through...

Answer 5

Sorry that's the total number of rounds
but not matches

Answer 6

Sure one moment I'll calculate

Answer 7

183+91+46+23+11+6+3+1+1=365

Answer 8

I did this and it gave me 360. But it may be wrong...
I need to check it by brute force

Answer 9

but there is no option as 360