What will be the remainder when sum of squares of all prime numbers greater than 3 but less than 100 is divided than 6
@sidsiddhartha @tkhunny @mathslover @ganeshie8 I got the answer as 23
@experimentX
Remainder? How could it be greater than 6?
There are 23 Prime Numbers between 3 and 100 (noninclusive) Find them. Add them up. Divide by 6. THEN you will have a Remainder.
wolf calculated it as 5 http://www.wolframalpha.com/input/?i=Mod%5BSum%5BPrime%5Bi%5D%2C+%7Bi%2C+3%2C+25%7D%5D%2C+6%5D but i don't know how to prove it.
I did it using a algebraic method
how did you represent the prime number?
@tkhunny its sum of the squares
woops!! sorry ...
We can represent prime numbers greater than 3 using the most unknown rule called "greater than three prime number rule" in mathematics
interesting ... could you give me links??
That's true. Square them before you add them up.
Actually it is very simple, but can be a usefull tool for such questions actually
The rule says that it is possible to represent prime numbers greater than 3 in the form (6n+1) and (6n-1) But its converse is not true
interesting to see that http://www.wolframalpha.com/input/?i=Mod%5BTable%5BPrime%5Bi%5D%2C+%7Bi%2C+3%2C+25%7D%5D%2C+6%5D
Yup, I heard the rule today
So 23 is the answer right?
23 mod 6 lol
No, no, no and no. We are dividing by 6. The REMAINDER must be 0, 1, 2, 3, 4, or 5
the remainder is 1 or 5 ... according to wolf. check the link i posted above.
or no remainder at all...
Options are (a) 23 (b)23/6 (c)30 (d)40
how are those remainders if you are dividing by 6?
looks like you added it all up ...
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