if log32=1.505 then what is the value of log_1000 32?
\[\log _{1000}32 \] that the second equation
im not sure what to do ??
soooo did a little time ith my notes and i got .502 by the change of base rule
is it correct??
the first line means log base 10 (10 is understood) \[ \log 32 = \log_{10} 32 = 1.505 \] you could use the change of base formula: \[ \log_{new\ base} x = \frac{\log_{old\ base} x}{\log_{old\ base} \text{new base}}\]
yay got it thank you thats what i used n___n @phi
log(1000) = 3 so you should get \[ log_{1000} 32 = \frac{1.505}{3} = 0.5017 \approx 0.502\]
yup thats it n_n thats what i got n_n thank you !! @phi
if you use a calculator or type into google 1000^(0.5017) = you will get close to 32. (we would need more digits to get exactly 32)
ohhhh ok then
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