Question

solve the equation below for x:
log2x+log(2x-1)=log3x

Answer 1

mmmhhh i dont really know how to start this process ???

Answer 2

base is 10 for all ?

Answer 3

if yes then hint
log(a.b)=log a + log b

Answer 4

it does not specified anything like that @ikram002p

Answer 5

Don't worry about base here

Answer 6

ok so first term is
log (2x)
not
\(\log_2 x\)
right ?

Answer 7

then use the hint i gave ^^

Answer 8

\[\log2x+\log(2x-1)=\log3x\] thats the equation

Answer 9

log2x+log(2x-1)=log3x

log(a.b)=log a + log b

log[2x(2x-1)]=log3x

Answer 10

ok i git u nw @meln_n ^^
can u use the Hint ?

Answer 11

mmmhhh im trying hehhe lets seee

Answer 12

log2x+log(2x-1)=log3x
log 2x*(2x-1) = log 9x
2x*(2x-1) = 3x
Now solve this for x.

Answer 13

yeah check @ShailKumar work ^