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Chemistry 19 Online
OpenStudy (anonymous):

A compound is 80% carbon and 20% hydrogen by mass, and has a molecular weight of 30.0 g/mol. determine the molecular formula

OpenStudy (somy):

Do you know how to find empirical formula?

OpenStudy (somy):

@Abmon98 =_= don't u dare tell everything

OpenStudy (somy):

let the asker think and try figuring out first

OpenStudy (anonymous):

yes empirical formula is the lowest ratio of a molecular formula

OpenStudy (somy):

okay can you do that here?

OpenStudy (anonymous):

the 30.0 g/mol is what is really messing me up on approaching it

OpenStudy (somy):

no this is not yet

OpenStudy (somy):

first it this percentages here can be considered to be 'mass' so you have mass, and you do know Mr of carbon and hydrogen atom so you can use mole formula

OpenStudy (somy):

u can find mole of H and C

OpenStudy (somy):

can you do that?

OpenStudy (anonymous):

so 80 g C and 20 g H. so like 6ish mol C and 20 mol H. So the formula would be CH3?

OpenStudy (somy):

no, wrong

OpenStudy (somy):

your way of thinking is right

OpenStudy (somy):

but the mole you get, you cannot round of

OpenStudy (anonymous):

well im trying to do this for standard testing so trying to not use a calc

OpenStudy (somy):

80/12= 6.666666667 moles 20/1= 20 moles remember that you have to divide both moles by the smallest

OpenStudy (somy):

oh well then it's okay i guess

OpenStudy (anonymous):

o maybe i shoulda rounded up for the carbon?

OpenStudy (somy):

oh btw lol u did it right

OpenStudy (anonymous):

o ok

OpenStudy (somy):

no its just when you find the moles, do not round them of and straightaway divide by the smallest

OpenStudy (somy):

it'll give you greater accuracy

OpenStudy (somy):

but yeah empirical formula is going to be CH3 as you said

OpenStudy (anonymous):

ok

OpenStudy (somy):

can you figure what to do next?

OpenStudy (anonymous):

CH3 is like 15 g? so since it is 30.0 g it would be double? so C2H6?

OpenStudy (somy):

good job!!

OpenStudy (somy):

but 15 is not gram its g/mole which is Mr

OpenStudy (somy):

do not confuse it with gram which is mass

OpenStudy (anonymous):

o my bad

OpenStudy (anonymous):

ye ok ty

OpenStudy (somy):

:D hope you understand now :)

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