Question

parabolas

Answer 1

Find the standard form of the equation of the parabola with a focus at (5, 0) and a directrix at x = -5.

Answer 2

https://answers.yahoo.com/question/index?qid=20080406123035AADW205

Answer 3

very good.... except for the fact that the address is not for my problem .-. @halorazer

Answer 4

No, it's not. I didn't say I'd give you the answer.

Answer 5

i didnt ask for an answer

Answer 6

If you follow the steps given then you could use them for your own question doe

Answer 7

nuuu it dosen't because i don't speak math and i do not understand where to get the letters from it explains half way.stating that y is the directrix but it doesn't explain for x, h, p, nor k

Answer 8

start by finding the vertex

Answer 9

wouldnt that be 0?

Answer 10

focus at (5, 0) and a directrix at x = -5.

vertex lies exactly half way between focus and directrix
so vertex = (5-5/2, 0) = (0,0)

Answer 11

yes !

Answer 12

and then what do i do c:

Answer 13

wait is 0 x, h, p or k?

Answer 14

since the parabola is centered at origin, you can use the equation from second column in attached table..

Answer 15

vertex = (h, k) = (0, 0)

Answer 16

\(\large x = \dfrac{1}{4c}y^2\)

Answer 17

so its 1/20y^2

Answer 18

Correct !!

Answer 19

thank you c:

Answer 20

np :)

Answer 21

do you have any more of those pictures for hyperbolas or ellipses

Answer 22

yes i have them for all conics

Answer 23

can i please have those c:

Answer 24

parabola with vertex at origin (0, 0)

Answer 25

parabola with vertex anywhere (h, k)

Answer 26

ellipses centered at origin (0,0)

Answer 27

ellipse centered anywhere (h, k)

Answer 28

hyperbola centered at origin (0,0)

Answer 29

hyperbola centered anywhere (h, k)

Answer 30

thats all you need for conics - 6 charts

Answer 31

oh thank you c:

Answer 32

yw :)