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A solution is prepared by dissolving 2 moles of a non-volatile solute in 4 moles of a volatile solvent. If the vapor pressure of the pure solvent is 24 torr, what will be the vapor pressure of the solution?
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you use: \(P_{solution}=\chi_{solute}*P_{solvent}^o\)
i keep getting 8, but the answer is 16 (2 moles/6 moles) * 24 torr=8?
sorry if forgot to include the delta sign it should be \(\Delta P_{solution}=...\) So to find the actual pressure you take the initial minus the change: \( P_{solution}=P^o_{solvent}-\Delta P_{solution}\)
o ok i got it
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