what would be the boiling point of a 2 m aqueous solution? Kb is 0.51 degrees Celsius/m for water and the BP of pure water is 100 degrees celsius

Question

aaronq · Answer

$\Delta T=i*m*K_B $

lena772 · Answer

why did you put that i in your formula? @aaronq

aaronq · Answer

i is called the van't hoff factor, it relates to the number of particles a given solute dissociates into. 

For example, for glucose it's $i$=1, but for NaCl, $i$=2.

aaronq · Answer

@Lena772

anonymous · Answer

um so is it 1* 2* 0.51? I am kinda lost as to what to do

aaronq · Answer

thats the change in temp. 

so the final BP is 100 + ( 1* 2* 0.51)=

anonymous · Answer

i get 101.02, but the answer is 101.2.

aaronq · Answer

i dont know what to tell you, that's how you do it. Are you 100% sure that the answer you have is correct?

anonymous · Answer

well its a copy of the answers from a practice packet. it might be wrong I will ask the instructor

aaronq · Answer

i think it might be a typographical error. you should ask your instructor though.

anonymous · Answer

ok thx

aaronq · Answer

no problem