A skater rotates at a speed of 10rad/s when her right hand & left leg are horizontally parallel to each other. Solve for the moment of inertia if the legs and hands are together. the moment of inertia when the leg&hand extend is 3 kg.m^2.

Question

anonymous · Answer

How do I solve this problem? What formula should I use?

vishweshshrimali5 · Answer

First of all you must use conservation of angular momentum

vishweshshrimali5 · Answer

Since no net external torque is being applied on the system, so angular momentum will remain conserved.

vishweshshrimali5 · Answer

Thus, we have,

$\large{I_{i}\omega_{i} = I_{f}\omega_{f}}$

vishweshshrimali5 · Answer

Now, you have $I_{i}$ and $\omega_{i}$.

vishweshshrimali5 · Answer

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