Question

Which represent the first two terms of the sequence: a1 = -2 and an = 2(an -1)^2?

Answer 1

2, -8
-8, -128
16, 1024
-2, 16

Answer 2

term \( a_1 \) is the first term
term \( a_2 \) is the second term

so u have \( a_1 \) try to find \( a_2 \)

Answer 3

hint : you don't need to do any calculations for solving this problem

Answer 4

Yeah pay attention on the power of \(a_{n}\)

Answer 5

* I meant in RHS of given expression.

Answer 6

just look at the options and use the fact that \(\large a_1 = -2\)

Answer 7

There is only option that has the first term = \(\large -2\)

Answer 8

yeah there is a problem in options ,
could u plz check A @sapphirelearner1995
to make sure its 2,-8
not -2, 8 ?

Answer 9

it is 2, -8
Did I write -2.8?

Answer 10

mmm idk *confused* ^_^

Answer 11

lol its okay @ikram002p

Answer 12

I am going to write the question in a better way:

\(\large{a_{n} = 2(a_{n-1})^2}\)

This was the expression @sapphirelearner1995 right ?

Answer 13

It should be -2, 8 in place of 2,-8 in option (A).

Answer 14

its\[a1 = 2\]

Answer 15

-,-

Answer 16

Ok then, also no option is right. Then, it should be 2,8 is option A.

Answer 17

hehe

Answer 18

attach the screenshot of problem

Answer 19

Your question was wrong .

Answer 20

i think \[a_{n}=2(a _{(n-1)})^{2}\]

Answer 21

It was \(\color{blue}{\text{Originally Posted by}}\) @vishweshshrimali5
I am going to write the question in a better way:

\(\large{a_{n} = \color{red}-2(a_{n-1})^2}\)

This was the expression @sapphirelearner1995 right ?
\(\color{blue}{\text{End of Quote}}\)

Answer 22

yes @vishweshshrimali5

Answer 23

Now, see, you have this:

(1) \(a_{1} = 2\)

(2) \(a_{n} = -2(a_{n-1} - 1)^2\)

Now, since you are given a1, so, using 2nd equation, you can find out a2 (Hint: put n = 2 in equation 2)

Answer 24

Can you find it @sapphirelearner1995 ?

Answer 25

either question is wrong or the options are wrong because it doesn't suit any options.

Answer 26

@neer2890 did you check the new one :

(1) \(a_{1} = 2\)

(2) \(\large{a_{n} = -2(a_{n-1} - 1)^2}\)

Answer 27

yup.

Answer 28

a1=2
a2=-2(2-1)^2
=-2*1=-2

Answer 29

Oh no no no. Its (n-1) in subscript

Answer 30

if it was like that then there wouldnt be 2 in there in first place

Answer 31

Yeah there must be given that n> 1

Answer 32

\[-2(2)^{2}\]
\[-2(4)=-8\]

Answer 33

\[1.a _{1}=2\]
\[2.a _{n}=2(a_{n-1})^{2}\]????

Answer 34

Nope thats -2 in RHS in 2nd equation

Answer 35

So the answer is \[2, -8\]

Answer 36

yeah ..typo :D

Answer 37

Yeah

Answer 38

Did you get it @sapphirelearner1995 ?

Answer 39

K, I am going with that! Thank you everyone! I'd give ya'll metals, but I can't so if people would give others metals to, that'd be awesome!

Answer 40

No problem. We would give each other medals. :D

Answer 41

I don't know if it's right (I'll tell everyone when I submit the test).

Answer 42

Ohh don't worry that's exactly correct.

Answer 43

It's right :)

Answer 44

:)