Question

What is the length of the conjugate axis?
((y-2)^2/16)-((x+1)^2/144)=1

Answer 1

im not sure if this is a vertical hyperbola if sooo then i know i need to use 2b to get the length

Answer 2

but what do i do with 2b ....?

Answer 3

it of the form
\[\frac{ (y-\beta)^2 }{ a^2}-\frac{ (x-\alpha)^2 }{ b^2 }=1\]
so length of conjugate axis will be\[\large 2b\]

Answer 4

would b = 4 thennn ???....

Answer 5

no compare those equations
u'll get
\[\large b^2=144\rightarrow b=12\]

Answer 6

2b = 2(24) = 48 ???

Answer 7

how
if b=12 then 2b=2*12=24

Answer 8

OPPPS my bad idk what was that lol

Answer 9

sorry lol mmmmhhhh okkk i understand now

Answer 10

thank you n_n @sidsiddhartha