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Mathematics 23 Online
OpenStudy (anonymous):

Modulus

OpenStudy (anonymous):

If the product of all the sollutions of the equation \[(x-2)^{2} -3\left| x-2 \right| +2 = 0 \] is

mathslover (mathslover):

You have to find the product of all the solutions of the equation, or is it given to you?

OpenStudy (anonymous):

Sorry i made a typo if is not there

OpenStudy (anonymous):

WE have to find the product

OpenStudy (rsadhvika):

say \(\large t = |x-2|\) the equation becomes \(\large t^2-3t+2 = 0\)

OpenStudy (anonymous):

x^2 -4x +4 -3x +6 +2 =0 x^2-7x +12 =0 (x-3(x-4) x=3 or 4

mathslover (mathslover):

x^2 - Sx + P = 0

OpenStudy (anonymous):

Okay we can solve that way too fine

OpenStudy (anonymous):

(t-1)(t-2)

OpenStudy (anonymous):

t =1 or t =2

mathslover (mathslover):

t^2 - 3t + 2 = 0 Product of solutions is "2"

OpenStudy (rsadhvika):

thats not the end

OpenStudy (anonymous):

it is 0

OpenStudy (rsadhvika):

|x-2| = 1 |x-2| = 2

OpenStudy (rsadhvika):

|x-2| = 2 gives one root as 0 so the product of roots will be 0 as you said

OpenStudy (anonymous):

ty

OpenStudy (rsadhvika):

yw

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