Find the lenght of time for: $500 to be intrest on $1800 at 6%p.a Find the rate percent per annum for: 15000 to be interest on $5400 for 5 years Find the principal required for The simple intrest to be $900 on an amount invested for 2 years at 10% p.a.
Assuming simple interest, the interest after 1 year is 1800 * 0.06. The number of years to reach a total amount of $500 interest is given by: \[\frac{500}{1800\times0.06}=you\ can\ calculate\]
So the answer is 4.63 right or125/27
Correct!
Thanks do uo you know how to do the others
Please check the values of the interest and the principal in the second part.
In the third part, let the principal amount be P. 900 = P * 0.1 * 2 \[P=\frac{900}{0.1\times2}=you\ can\ calculate\]
1500 to be interest on $5400 for 5 years
sorry got the Question wrong for second part
For the second part, assuming simple interest, let the interest rate as a decimal be r. 1500 = 5400 * r * 5 \[r=\frac{1500}{5400\times5}=you\ can\ calculate\]
=6%
For the second part, I get a yearly interest rate of approximately 5.55%.
Hey i got another question $3200 at 10.25% p.a for 2 1/2 years compounded - 3 monthly
\[A=P(1+\frac{r}{n})^{nt}\] \[A=3200(1+\frac{0.1025}{4})^{2.5\times4}\]
Wait how did u get 4
In the general equation, n is the number of compounding intervals per year. In your question the interest is compounded 3-monthly, giving 4 compounding intervals per year.
oh k
so the answer is 1053655670
ops wrong answer
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