Question

find the all values of x for which f(x)=0 let f(x)=x^-5x+6

Answer 1

nhof ,

is it : f(x) = \(\large x^{-5x +6}\) or f(x) = \(x^2 - 5x + 6\) ?

Answer 2

probably the later
f(x)=0 means that your f(x) value is zero
so let's use substitution and solve for x
0=x^2-5x+6
I would factor the right side and solve each factor.
This is a quadratic (ie 2nd power) and you should have 2 solutions.

Answer 3

x^2-5x+6
(x-2)(x-3)
x-2=0 x-3=0
x=2 x=3