how to rewrite this equation into a*b^x?

Question

anonymous · Answer

$$5(3)^{2x-4}$$

solomonzelman · Answer

$\large\color{midnightblue}{ \rm  a^{b-v}=a^b/a^v }$  your b is 2x, and your v is 4

anonymous · Answer

wait ummm what? I don't understand

terenzreignz · Answer

Me neither. What is it exactly, that you want?
I looks like it's already in the form you want...

anonymous · Answer

it has to be in the form of $$a \times b ^{x}$$

anonymous · Answer

a has to be a number and b has to be an number but only x can be the exponent it can't have 2x-4

terenzreignz · Answer

Sorry, I spaced out. Yeah, okay... first, use this bit of knowledge:
$$\Large a^{m-n}= \frac{a^m}{a^n}$$

terenzreignz · Answer

And simplify
$$\Large 3^{2x- 4}$$

anonymous · Answer

Ohhh 
ok
Thanks a million guys!!

geerky42 · Answer

$3^{2x} \neq 3^23^x$...

anonymous · Answer

yeah ok wait so what do I do?

geerky42 · Answer

Yeah ... , $\Large 3^{2x} = \left(3^2\right)^x$

geerky42 · Answer

Sorry for careless mistakes... So do you know what to do now?

anonymous · Answer

$$5(\frac{ 3^2 }{ 3^{4}})^{x}$$

anonymous · Answer

is B= $$\frac{ 1 }{ 9 }$$

geerky42 · Answer

None. should be $\Large 5\left(\dfrac{(3^2)^x}{3^4}\right) = \dfrac{5}{3^4}9^x$

geerky42 · Answer

a is 5/(3^4) and b is 9

geerky42 · Answer

is that clear?

anonymous · Answer

what's wrong with what I got?

geerky42 · Answer

See the formula terenzreignz gave you? you were supposed to split 3^(2x-4) to this:$$\Large \dfrac{3^{2x}}{3^4}$$

geerky42 · Answer

does that help?

anonymous · Answer

yeah thanks