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Chemistry 10 Online
OpenStudy (anonymous):

Ammonia is produced by the following reaction. 3H2(g) + N2(g) --------> 2NH3(g) When 7.00 g of hydrogen react with 70.0 g of nitrogen, hydrogen is considered the limiting reactant because 7.5 mol of hydrogen would be needed to consume the available nitrogen. 7.5 mol of nitrogen would be needed to consume the available hydrogen. hydrogen would produce 7.5 mol more ammonia than nitrogen. nitrogen would produce 7.5 mol more ammonia than hydrogen.

OpenStudy (somy):

find mole of both H and N

OpenStudy (somy):

the one with a least mole is going to be your limiting reagent

OpenStudy (anonymous):

hydrogen but why

OpenStudy (somy):

because u have less of H in reaction so that means the reaction will depend on amount of H

OpenStudy (anonymous):

so whats the answer then

OpenStudy (somy):

this is kinda confusing @aaronq

OpenStudy (anonymous):

;-(

OpenStudy (anonymous):

I have 6 questions left and 10 minutes :-(

OpenStudy (somy):

only A makes sense kinda though im struggling to prove it

OpenStudy (somy):

im so sorry T_T

OpenStudy (anonymous):

its fine i entered A

OpenStudy (anonymous):

The actual yield of the products in a reaction is always $________$ the theoretical yield. greater than the same as less than the mole ratio of

OpenStudy (somy):

could u tell me what do u think?"

OpenStudy (anonymous):

greater

OpenStudy (somy):

no its actually the opposite

OpenStudy (somy):

u've gotta remember that Actually yield is always less the theoretical

OpenStudy (anonymous):

ahhhhh thank u

OpenStudy (somy):

http://www.bbc.co.uk/schools/gcsebitesize/science/add_ocr_21c/chemical_synthesis/synthesisrev4.shtml make sure to read this afterwards to understand why so, ok?

OpenStudy (somy):

u r welcome :)

OpenStudy (anonymous):

i WILL

OpenStudy (anonymous):

omg my times running out ;-(

OpenStudy (somy):

if there is any more question make sure to open a new question and always medal the person whose answer you consider to be right/ understand/ useful

OpenStudy (anonymous):

how do you medalsomeone

OpenStudy (somy):

and Welcome to OS :)

OpenStudy (anonymous):

i just did it

OpenStudy (anonymous):

ok ill post my new ques

OpenStudy (somy):

yeah like that anyways lets go back to ur questions

OpenStudy (somy):

okay)

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