how do I solve: . A 5-kg fish swimming at 1 m/s swallows an absentminded 1-kg fish swimming toward it at a velocity that brings both fish to a halt. Show that the speed of the smaller fish before lunch was 5 m/s.
Hello @beccamarx19 !
Let the speed of the small fish before lunch be x m/s
Now by using Principle of conservation of linear momentum (m1v1 = m2v2)
-5 * 1 + x * 1 = 0
Solving this we get x = 5
got it ?
how did you get that?
i got that never mind
are uh sure ?
if it is -5*1 it equals -5 then x*1 =0 -5+5 equal 0
No, -5*1 + 1*x = 0, then, -5=-x, then, 5=x
meaning x has to be 5 in order for it all to equal 0
yes
right i think i got it thank you
Did you know you can give medals to people who help you with questions? Just click the \(\color{blue}{\text{blue "best response" button}}\) to show appreciation for the people who help you.
Feel free to tag me in if u hav more doubts \(\color{green}{\huge\ddot\smile}\)
how do i do that i posted another question already
just add @ with anyones name u want to tag like if u want to tag me write @abhisar
Join our real-time social learning platform and learn together with your friends!