how do I solve:
. A 5-kg fish swimming at 1 m/s swallows an absentminded 1-kg fish swimming toward it at a velocity that brings both fish to a halt. Show that the speed of the smaller fish before lunch was 5 m/s.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (abhisar):
Hello @beccamarx19 !
OpenStudy (abhisar):
Let the speed of the small fish before lunch be x m/s
OpenStudy (abhisar):
Now by using Principle of conservation of linear momentum (m1v1 = m2v2)
OpenStudy (abhisar):
-5 * 1 + x * 1 = 0
OpenStudy (abhisar):
Solving this we get x = 5
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (abhisar):
got it ?
OpenStudy (anonymous):
how did you get that?
OpenStudy (anonymous):
i got that never mind
OpenStudy (abhisar):
are uh sure ?
OpenStudy (anonymous):
if it is -5*1 it equals -5 then x*1 =0 -5+5 equal 0
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (abhisar):
No,
-5*1 + 1*x = 0,
then, -5=-x,
then, 5=x
OpenStudy (anonymous):
meaning x has to be 5 in order for it all to equal 0
OpenStudy (abhisar):
yes
OpenStudy (anonymous):
right i think i got it thank you
OpenStudy (abhisar):
Did you know you can give medals to people who help you with questions? Just click the \(\color{blue}{\text{blue "best response" button}}\) to show appreciation for the people who help you.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (abhisar):
Feel free to tag me in if u hav more doubts \(\color{green}{\huge\ddot\smile}\)
OpenStudy (anonymous):
how do i do that i posted another question already
OpenStudy (abhisar):
just add @ with anyones name u want to tag like if u want to tag me write @abhisar