Question

How do I solve:?
Show that 480 W of power is expended by a weightlifter when lifting a 60-kg barbell a vertical distance of 1.2 m in a time interval of 1.5 s.

Answer 1

Power = \[\frac{ Work~done }{ Time~taken }\]

Answer 2

480/1.5?

Answer 3

\[Work = F X distance\]

Answer 4

680?
480?

Answer 5

explain

Answer 6

Here weight is 600, so force require to lift it will be 60X10=600N

Answer 7

Now work = 600X1.2=720J

Answer 8

Power=720/1.5=480W

Answer 9

LOL..damn typo..weight is 60Kg so Force = 60X10=600

Answer 10

got it ?

Answer 11

yes i do

Answer 12

Sure ?

Answer 13

yep

Answer 14

That's gr8 !
\(\color{green}{\huge\ddot\smile}\)