Question

The displacement of a body with time t is related as S=ae^6t - be^-4t. Find the rate of change of displacement with respect to time t.

Answer 1

hasn't this one been solved already?

Answer 2

what you mean?

Answer 3

\[S = ae ^{6t}-be ^{-4t} \rightarrow
S \prime= ae ^{6t}.(6)-be ^{-4t}.(-4)\]

so what's next ?

Answer 4

@geerky42
where is you :(

Answer 5

That it. you solved it.

Answer 6

\[S = ae ^{6t}-be ^{-4t} \rightarrow S \prime= ae ^{6t}.(6)-be ^{-4t}.(-4) \]
this is solution ?

Answer 7

actually, simplify it a little but, multiply -4 by -be^(-4t) and something like that

Answer 8

\[\dfrac{dS}{dt} = \boxed{6ae^{6t}+4be^{-4t}}\]This is solution

Answer 9

aha .. thanks @geerky42

Answer 10

6ae^(6t) + 4be^(-4t)

Answer 11

thank you @cwrw238