a standard deck of card contains 52 cards. one card is selected from the deck.
a. p(heart or spade)
b.p(heart or spade or diamond)
c. p(queen or spade)
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OpenStudy (anonymous):
i think a. is 1/4
b.3/4
OpenStudy (anonymous):
but my best guess for c is 17/52 im not sure if that right
OpenStudy (kropot72):
a. The probability of heart or spade is:
P(heart) + P(spade)
There are 13 cards in each suit, so:
P(heart) + P(spade) = 13/52 + 13/52 = you can calculate
OpenStudy (anonymous):
so 1/2
OpenStudy (kropot72):
b. The probability of heart or spade or diamond is:
P(heart) + P(spade) + P(diamond) = 13/52 + 13/52 + 13/52 = 3/4
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OpenStudy (anonymous):
yay i got that right
OpenStudy (kropot72):
Yes, 1/2 is correct for a.
OpenStudy (anonymous):
for c i keep coming up with 17/52
OpenStudy (anonymous):
=.33
OpenStudy (anonymous):
is c right
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OpenStudy (anonymous):
a.) 1/2
b.) 3/4
c.)17/52 or .33
OpenStudy (anonymous):
thank you
OpenStudy (kropot72):
There are 12 cards in the suit of spades without the queen of spades. And there are 4 queens;
So:
P(queen or spade) = 4/52 + 12/52 = 4/13
OpenStudy (anonymous):
c.)
p(queen)+p(spade)=4/52+13/52=17/52 or.33
OpenStudy (anonymous):
oh thank you again
i forgot you can count something twice
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