Question

In the diagram, the two circles are tangent at point K. PS=20, ST=6, and NM=22. Find PN. If necessary, round to the hundredths place.

Answer 1

Where is diagram?

Answer 2

two circles are tangent at one point
means they are touching,right?

Answer 3

or idk
post the diagram pls

Answer 4

this is easy
do you know tangent secant relation

Answer 5

no

Answer 6

first you will have to find PK

Answer 7

(PK)^2 = PS (PS+ST)

Answer 8

now you know ps,and st
find pk

Answer 9

....

Answer 10

\[pk^2=20(20+6)\]
\[pk^2=400+120\]
\[pk^2=520\]

Answer 11

pk=22.80?

Answer 12

yes
now you have to find PN

Answer 13

so here
PK^2 = PN(PN+ NM)

Answer 14

520 = PN^2 +22PN

Answer 15

you will have to solve it

Answer 16

to get the answer

Answer 17

would PN be the same as PK?

Answer 18

solve it by quadratic formula
see what you get
\[x = \frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]
a=1 b=-22
c= -520

Answer 19

okay i got x=36.31

Answer 20

i got the same :)
thats correct then

Answer 21

Awesome thanks :) sorry i just really dont understand this

Answer 22

hahaha
you will get used to it