Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (vera_ewing):

Write an equation that could be used to find the value of b. http://curriculum.kcdistancelearning.com/courses/GEOMx-HS-A09/b/assessments/R-LawsofSinesandLawofCosinesQuiz/Geometry_8.4_Quiz_FINAL_20q.png

OpenStudy (vera_ewing):

@marissalovescats it's b2 = 132 + 122 – 2(13)(12)(cos 14°) right?

OpenStudy (marissalovescats):

Yes except it's cos 41 not 14

OpenStudy (marissalovescats):

And 13^2 is 169 not 132

OpenStudy (vera_ewing):

b2 = 122 + 132 – 2(12)(13)(cos 41°) b2 = 412 + 132 – 2(41)(13)(cos 12°) b2 = 132 + 122 – 2(13)(12)(cos 14°) b2 = 122 + 132 + 2(12)(13)(cos 41°)

OpenStudy (vera_ewing):

which one?

OpenStudy (marissalovescats):

Are these really your answer choices?

OpenStudy (vera_ewing):

yeah they are...

OpenStudy (vera_ewing):

oh wait sorry hold on...

OpenStudy (vera_ewing):

b^2 = 12^2 + 13^2 – 2(12)(13)(cos 41°) b^2 = 41^2 + 13^2 – 2(41)(13)(cos 12°) b^2 = 13^2 + 12^2 – 2(13)(12)(cos 14°) b^2 = 12^2 + 13^2 + 2(12)(13)(cos 41°)

OpenStudy (marissalovescats):

b^2=a^+c^2-2(a)(c)CosB b^2=12^2+13^2-2(12)(13)Cos41 b^2=144+169-2(12)(13)Cos41 That what it should be... but it would have to be the 1st one I guess

OpenStudy (vera_ewing):

b^2 = 12^2 + 13^2 – 2(12)(13)(cos 41°) ?

OpenStudy (marissalovescats):

Yes

OpenStudy (vera_ewing):

thank you! :D

OpenStudy (marissalovescats):

Thats why I was confused I was like 122 and 132??? Where are they getting that from? Lol

OpenStudy (vera_ewing):

yeah haha i didn't notice that lol

OpenStudy (marissalovescats):

That's okay haha

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!