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Chemistry 10 Online
OpenStudy (anonymous):

Calculate the wavelength (λ in nm) of the photon emitted when an electron transitions between n = 3 and n = 1 energy levels. I keep getting .00975 but the answer is apparently 102.6nm could someone please explain this to me?

OpenStudy (somy):

dsinQ=nLambda

OpenStudy (somy):

lambda= ( d * sinQ )/ n

OpenStudy (somy):

ah wait its not what you need, sorry

OpenStudy (somy):

can u show your working?

OpenStudy (jfraser):

0.00975 is the INVERSE of the wavelength. If you divide 1/0.00975 you'll get 102nm

OpenStudy (anonymous):

Thanks Fraser that's exactly what i needed

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