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OpenStudy (anonymous):
Which expression is equivalent to 4^1/3 times 4^1/6
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OpenStudy (anonymous):
The Equation written better:
\[4^{1/3}*4^{1/6}\]
The Choices:
\[A: 2\]
\[B: 16\]
\[C: \sqrt[3]{4}\]
\[D: \sqrt[6]{16}\]
jimthompson5910 (jim_thompson5910):
The bases are the same, so you add the exponents.
jimthompson5910 (jim_thompson5910):
1/3 + 1/6 = ???
OpenStudy (anonymous):
\[\frac{ 1 }{ 3 } + \frac{ 1 }{ 6 } = \frac{ 1 }{ 9 }\]
jimthompson5910 (jim_thompson5910):
no
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jimthompson5910 (jim_thompson5910):
you cannot add the denominators like that
OpenStudy (anonymous):
Oh okay that's only with multiplication where you don't have to change the denominators into a common denominator. Oops. Brain fart.
So it's:
\[\frac{ 1 }{ 3 } = \frac{ 2 }{ 6 }\]
\[\frac{ 2 }{ 6 } + \frac{ 1 }{ 6 } = \frac{ 3 }{ 6 } =\frac{ 1 }{ 2 }\]
jimthompson5910 (jim_thompson5910):
very good
jimthompson5910 (jim_thompson5910):
so "4^1/3 times 4^1/6" turns into 4^(1/2)
jimthompson5910 (jim_thompson5910):
anything to the 1/2 power is really taking the square root
that means
\[\Large 4^{1/2} = \sqrt{4}\]
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jimthompson5910 (jim_thompson5910):
because I'm using the rule
\[\Large x^{m/n} = \sqrt[n]{x^m}\]
OpenStudy (anonymous):
Which means that the answer is 2?
jimthompson5910 (jim_thompson5910):
correct
OpenStudy (anonymous):
Thank you so much!
jimthompson5910 (jim_thompson5910):
np
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