Question

Factor x^3 + 2x^2 9x - 18, given that -2 is a zero.

Answer 1

You could do synthetic division and then it will be facorable

Answer 2

Option A: (x 2)(x2 9) = 0

Option B: (x + 2)(x 3)(x + 3) = 0

Option C: (x 2)(x 3)(x + 3) = 0

Option D:
\[(x+2)(x-\sqrt{3})(x+\sqrt{3})=0\]

Answer 3

x^2+2x^2+9x-19 right?

Answer 4

yes

Answer 5

That one can't be solved by synthetic

You'll know that the factor will have x+2 in it because -2 is a solution

Answer 6

So that eliminates A and C

Answer 7

And we know the first one can't be it because of the x^3, you'll have to multiply is by x twice and get x^5 which doesn't fit in

x^3 + 2x^2 9x - 18

Answer 8

So that leaves D

Answer 9

Choice B does say:

(x+2)(x^3)(x+3)

Right?

Answer 10

no it says (x+2)(x-3)(x+3)-0
my minus signs stick and don't always appear

Answer 11

Oh then yes B is the answer