Question

Am I doing this wrong?

What is the solution of log2x − 6 256 = 4?
I'm trying to find the value of x but when I plug in x nothing equals out to 4.

Answer 1

\[\log(2x-6)*256=4\]

Answer 2

x = −5

x = −4

x = 4

x = 5
Here are my choices.

Answer 3

@hartnn

Answer 4

2x-6 is the base, right ?

Answer 5

Correct

Answer 6

\(\huge \log_{(2x-6)}256=4\)

Answer 7

(2x-6)^4 = 256

Answer 8

4^4 = 256

Answer 9

which gives
2x-6 = 4

Answer 10

now get x

Answer 11

Okay.. But wouldn't be easier to just plug in the x values into the equation or would it not work?

Answer 12

And x would equal 5

Answer 13

sometimes plugging in is easier, sometimes its not.
if you know log rules, then this is much easier to actually solve rather than trying out all choices

Answer 14

Okay, I appreciate the help!

Answer 15

now verify
plug in 5

Answer 16

its 5