How many grams of iron metal do you expect to be produced when 245 grams of an 80.5 percent by mass iron (II) nitrate solution reacts with excess aluminum metal? Show all of the work needed to solve this problem.

2 Al (s) + 3 Fe(NO3)2 (aq) yields 3 Fe (s) + 2 Al(NO3)3 (aq)

Question

How many grams of iron metal do you expect to be produced when 245 grams of an 80.5 percent by mass iron (II) nitrate solution reacts with excess aluminum metal? Show all of the work needed to solve this problem. 

2 Al (s) + 3 Fe(NO3)2 (aq)  yields 3 Fe (s) + 2 Al(NO3)3 (aq)

anonymous · Answer

So far I have
245 g Fe(NO3)2 x (80.5 g Fe(NO3)2 solute/ 100 g Fe(NO3)2) x ( 1 mol Fe(NO3)2/ 179.85 g Fe(NO3)2) x (1 mol Al/2 mol Fe(NO3)2) x (26.98 g Al/1 mol Al)

anonymous · Answer

I don't know what to do from here please help

australopithecus · Answer

2 Al (s) + 3 Fe(NO3)2 (aq) -> 3 Fe (s) + 2 Al(NO3)3 (aq)

0.8*245 grams  = Grams of iron (II) nitrate

Next convert to moles

moles = gram/molecular mass

molecular mass can be determined from the periodic table just look up a youtube video if you dont know how to find it.

From your formula for every 3 atoms of  Fe(NO3)2 reacted 3 atoms of Elemental Iron are produced.

So divide the moles by 3, then multiply by 3 to receive the amount of moles of elemental Iron, this gives you the moles of elemental iron produced.

Then convert from moles to grams using the formula provided above

Alternative way you could solve this is simply by using gravimetric factor (look it up) assuming the reaction goes to completion and conservation of mass you could just find the amount of iron in 0.8*245 grams of Iron (II) nitrate in one simple calculation

anonymous · Answer

can someone help me through the steps?? please I need to do this or ill get kicked out of my course :(

abmon98 · Answer

Mass:80/100*245=197.225
Molar mass of iron natrate:179.8
Number of moles:Mass/Molar Mass
Number of moles=197.225/179.8
Number of moles=1.096
Ratio of iron metal to iron nitrate is 3:3 so they share the same number of moles
1.096*55.8=61.2grams

anonymous · Answer

I got 61.435?

anonymous · Answer

0.805 x 245g = grams of iron II nitrate
197.26 = grams of iron II nitrate

moles = grams / molecular mass
moles = 197.26/ 179.845
moles = 1.10

1.10 moles Iron 
grams = moles x molecular mass
grams = 1.10 x 55.85
grams = 61.435

abmon98 · Answer

thats right

anonymous · Answer

okay cool thanks(:

abmon98 · Answer

your welcome :)