Question

If 5.0 liters of carbon dioxide gas are produced by the reaction below at STP, how many liters of oxygen gas were used in the reaction?
2 CO (g) + O2 (g) ---> 2 CO2 (g)

Answer 1

10.0 L

7.5 L

5.0 L

2.5 L

Answer 2

one mole of gas occupies 22.4 liters,
5*1/22.4=0.22 moles of carbon dioxide ration of oxygen to carbon dioxide is 1:2
so we divide 0.22 by 2 we get 0.11 moles of oxygen
1 mole occupies 22.4 litres, what if 0.11 moles of oxygen were used what volume would it occupy. so 0.11*22.4/1=2.5L

Answer 3

Thank you!