ΔABC is a right triangle where m∠B = 90°. The coordinates of A and B are (5, 0) and (2, 5), respectively. If the x-coordinate of point C is 7, what is the y-coordinate of C ? A. 5 B. 7 C. 8 D. 10
you're given : A = (5, 0) B = (2, 5)
say C = (7, y)
but how do you find the y coordinate?
use below : product of slopes of perpendicular lines = -1
find the slope of AB find the slope of BC
set the product equal to -1 and solve y
can you find the slopes ?
i knew how to do it before but i haven't done it in so long so i forgot how loll
easy, use the slope formula http://www.algebra-class.com/image-files/slope-formula-2.gif
A = (5, 0) B = (2, 5) slope = ?
i got 5/-3 after i subtracted them. I think i did it wrong
Correct !
next, find the slope of BC
B = (2, 5) C = (7, y) slope = ?
im assuming you set the product of y=-1. So using that in the formula I got -6/5 for the slope
that comes later, first we need to find the slope in terms of y : B = (2, 5) C = (7, y) slope = (y-5)/(7-2) = (y-5)/5
now set the product of both slopes equal to -1 : (5/-3)((y-5)/5) = -1 solve y
im thinking the slope is 8. Idk if i solved for y correctly or not
5 cancels out and you will get : (y-5)/-3 = -1 y - 5 = 3 y= 8
good job !!!
lml i got it right ! :D
thank you ganeshie ur the besttt
no, you're the best !! yw :)
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