Question

The equation of an ellipse is given by (x+2)^2/49 + (y-4)^2/25 = 1
Find the coordinates of the foci.

Answer 1

@marissalovescats help?

Answer 2

"a' is the BIGGER denominator and is under the fraction with the "x" variable, meaning the ellipse has an horizontal major axis thus \(\bf \cfrac{(x-{\color{blue}{ h}})^2}{a^2}+\cfrac{(y-{\color{blue}{ k}})^2}{b^2}=1
\\ \quad \\
{\color{olive}{ c}}\to \textit{distance from the center to either focus point}\to \sqrt{a^2-b^2}
\\ \quad \\
thus \qquad foci\ ({\color{blue}{ h}}\pm {\color{olive}{ c}}, {\color{blue}{ k}})\)

Answer 3

So it's 9.78?

Answer 4

? foci is 2 and each is a point thus an ordered pair

Answer 5

Oops that was the answer to a different question ignore that one