Question

logarithms anyone?! x_0

Answer 1

no? :'(

Answer 2

you need to post the question then someone will be happy to help

Answer 3

yeeey

Answer 4

here it is: http://oi57.tinypic.com/nbavlv.jpg

Answer 5

i know it's (1/3,1] i just need the whole process

Answer 6

log (3)x + log(3)x^2 = log(3)x^0;I am using (3) to represent base 3

Answer 7

could you use the equation option it's hard for me to follow like this :/

Answer 8

when you add logs , multiply the numbers

Answer 9

x*x^2=? i know that but i don't know what to do in the end when i sort all that out ...

Answer 10

x^0 =1

Answer 11

i got to this : \[2^{3\log_{3}x ^{3} }=2\] and i don't know what to do next..

Answer 12

without the 3 on x just 3log(3) x

Answer 13

log(3)x^3 = log(3)0=1
log (3)x^3 = 1
X^3=1 ALSO 3 Log(3)x = 1
X = 1

Answer 14

and the other one 1/3 ?

Answer 15

also 3log(3)x=1
so log(3)x= 1/3
x = 3

Answer 16

no no the other solution is x=1/3 not 3

Answer 17

i am trying to remember
x^3 = is one solution and the other is using the 3 with the log so
it would be 1/3
but

Answer 18

yea i get the previous answer but apparently there's something more to it..i tried to even do it with t like a shift but i get to the same point.. :/

Answer 19

x = 3^1/3 = 1/3 log(3)3 = 1/3*1 = 1/3

Answer 20

finally!

Answer 21

let me explain what i have , og(3)x^3 = log(3)0=1
log (3)x^3 = 1
X^3=1 ALSO 3 Log(3)x = 1
X = 1

Answer 22

using 3 log(3)x =1
log (3)x =1/3
x =3^1/3 = 1/3 log(3)3 log(3)3 =1

Answer 23

got it ..thank you! :D
i didn't know that i could shift the 3 on the other side :)

Answer 24

logs are fun and easy but have to remember how to convert bases etc
sorry it took so long

Answer 25

it's okay..at least you replied :D
i totally gave up on it ..and started doing something else,'cause i couldn't find the other answer xD

Answer 26

math is fun logs are extremely easy compared to something like calculus with analytical geometry
glad I could help

Answer 27

:)