Question

Choose the correct product of (2x - 4)^2.

4x^2 - 16

4x^2 - 16x + 16

4x^2 + 16

4x^2 + 16x + 16

Answer 1

4x^2 - 16x + 16

Answer 2

To solve this problem, all we need to do is FOIL the binomal. So, we will multiply the terms according to their position. First, you multiply both terms that are first in the binomial. Since the problem is just one binomal, but squared, it may be easier for us to write it out completely.\[(2x-4)(2x-4)\]Now, we multiply the first terms\[2x*2x=4x ^{2}\]Next comes the O in FOIL, which is the outer terms. Here, we multiply the two terms which are on the edge of the binomial.So here, we multiply 2x and -4\[2x*-4=-8x\]According to the I in FOIL, we then need to multiply the inner terms. Since they are the same, we get -8x again. Finally, we multiply the last terms in each binomial\[-4*-4=16\]Now we just take what we have and simplify it\[4x ^{2}-8x-8x+16\]\[4x ^{2}-16x+16\]This is our final answer.

Answer 3

I answer the question by this formula.
\[( ax - b)^{2} = (a x)^{2} -2abx + b^{2}\]
a=2, b = 4
It's finish.