You have a normal distribution of hours per week that music students practice. The mean of the values is 8 and the standard deviation of the values is 4. According to the normal distribution model that corresponds to this population, what percentage of the students practice between 6 to 10 hours per week?
first you find the z scores...
\[ z = \frac{x-\mu}{\sigma} \]So \(\mu\) is average, \(\sigma\) is the standard deviation, and \(x\) is the value.
so you need to find \(z\) that corresponds to 6 and the \(z\) that corresponds to 10.
Would u be 16?
I think the answer is 34?
wait, have you found the z scores yet?
34%
where are you stuck? how did you get the answers?
Yeah 16 right? I'm estimating
Okay I think I've figure it out thanks for the help
oh, you are guessing because it is withing a standard deviation?
Yeah
okay you wanna do this: http://www.wolframalpha.com/input/?i=within+half+standard+deviation
it should be 'confidence level'
Oh I see thanks!
So the answer is 38%
Yeah, I think so.
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