Question

differentiate 2t^(-3/4)

Answer 1

Simple rule,

f(x) = x^n
f'(x) = nx^(n-1)

Answer 2

where n is just a number

Answer 3

can you solve this now?

Answer 4

i will try! thanks!

Answer 5

so just subtract -3/4 with one and bring that down and multiply by 2 because its 2(-3/4)?

Answer 6

yes

Answer 7

thats it? so answer is -3/2t^(-7/4)?

Answer 8

This document has all the important derivative rule you need to practice and memorize, it also covers a general calc 1 courses material till the final exam.

Answer 9

thank you for that document it will help since my professor just do one problem and then gives rest for homework

Answer 10

no that is wrong,

f'(x) = (-3/4)2^(-3/4 - 1)
f'(x) = (-3/4)2^(-3/4 - 4/4)
f'(x) = (-3/4)2^(-7/4)

Answer 11

so,

\[\frac{-3(2)^{-7/4}}{4}\]

Answer 12

you need to practice these rules like crazy until you can look at a function and know its derivative almost automatically

Answer 13

where did the t go?

Answer 14

i am lost

Answer 15

lol sorry made a mistake out of practice

Answer 16

\[\frac{(-3)(2)t^{-7/4}}{4}\]

Answer 17

the rule is very simple, just go through your homework, I cant stress practice problems enough when it comes to calculus

Answer 18

i thought (-3/4)(2)t^(-7/4) would be the answer

Answer 19

yeah that is the answer

Answer 20

remember basic multiplication of fractions

Answer 21

so just multiply -3/4 * 2

Answer 22

(-3/2)t^(-7/4) that is correct multiplication?

Answer 23

\[\frac{-3}{4}(\frac{2t^{-7/4}}{1}) = \frac{-6t^{\frac{-7}{4}}}{4*1} = \frac{-6}{4t^{\frac{7}{4}}}\]

Answer 24

yeah that is fine i'm just crazy tired

Answer 25

yeah i was like if you just multiply and stuff we get same answers you just put it in different way

Answer 26

that can be simplifed to -3/2t^(7/4)

Answer 27

sorry man losing my mind lol

Answer 28

lol no problem! thanks for the help though i thought i was doing it write but i just wanted to make sure haha