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differentiate: j(x) = x^2.4+e^2.4
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@ikram002p
just bring down the power and subtract with 1?
e is the math e
so like this \( j(x) = x^2.4+e^2.4 \) yep ur correct :D
no its x^(2.4) + e^(2.4)
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so 2.4x^(1.4) +2.4e^(1.4)?
no lol e^2.4 is a nummer=constant
i thought both of them sry
It would be 2.4x^1.4 + e^2.4. the derivative of e to the anything stays the same.
so for x part ur correct but for e^1.4=0
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oh thank you!
lol whats ur answer ?
2.4x^(2.4-1) +e^2.4 2.4x^(1.4)+e^2.4
incorrect
e^2.4 is constant like C
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so 0 for e
yep
2.4x^1.4 thats the answer
yess :)
Thank you!!
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np :)
another question i will tag you
ok post
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