Question

Find the zeros of g(x)=5(x+6)^2(x^2-36)(x-6)? I'll give a metal to whoever can solve this for me!

Answer 1

the equal is supposed to be a plus before the six
my bad!

Answer 2

x=-6 with multiplicity: 2, 6,-6,6 I think

Answer 3

thanks!

Answer 4

To find the roots/zeros of the function, set the function equal to 0 and solve.

If any individual factor on the left-hand side of the equation is equal to 0, the entire expression will be equal to 0.

Set the first factor equal to 0 and solve.

Then, set each of the factors equal to 0 and solve.

e.g.

(x+6)

x+6=0

x=-6

don't forget to take both positive and negative square root possibilities as zeroes.

Answer 5

Set g(x) = 0

0=5(x+6)^2(x^2-36)(x-6)

Divide both sides by 5
0 = (x + 6)^2(x^2 - 36)(x - 6)

Use zero product property at this point:
0 = x + 6
0 = x - 6