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OpenStudy (anonymous):
@mathslover
OpenStudy (anonymous):
|dw:1403001476904:dw|
mathslover (mathslover):
l = ? (u know the formula? )
mathslover (mathslover):
\(\sqrt{l(l+1) } \times \cfrac{h}{2\pi}\)
what is l for 3p orbital?
OpenStudy (anonymous):
Is it root
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mathslover (mathslover):
yep..
orbital angular momentum = \(\sqrt{l(l+1)} \cfrac{h}{2\pi}\)
OpenStudy (anonymous):
O_o Ncert mw without root likha hai
S orbital ke liye to without root kuch farak nahi padta
so i got the first answer
But for p i got 1/pi
according to ncert "so called formula"
abhi answer milgaya
OpenStudy (anonymous):
Ncert has without root lol
mathslover (mathslover):
:-) koi nahin, answer aa gaya na? bass toh fir party karte hain.. :P
OpenStudy (anonymous):
angular momentum of 4th bohr orbit?
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mathslover (mathslover):
hmm, try kiya?
OpenStudy (anonymous):
milgaya sorry
mathslover (mathslover):
:)
OpenStudy (anonymous):
wait is it 2h/pi
mathslover (mathslover):
l kya hota hai 4th bohr orbit ke liye?
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OpenStudy (anonymous):
I used mvr=nh/2pi
mathslover (mathslover):
okay, so u just put n = 4 there, right?
OpenStudy (anonymous):
yeah
mathslover (mathslover):
seems right to me.
OpenStudy (anonymous):
you are attending the plancess ........
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