can someone do this math problem?
Shoot.
hold on i mesed up
Both the vertical dominoes have to appear in the same pair of rows - that is, both the vertical dominoes should have their ends in first and second row, or second and third row. : Otherwise, the top and bottom rows will have 51 cells to be filled by horizontal dominoes, which is not possible. Also, we need to ensure that the three pieces the vertical dominoes divide the rows into should all have even length so that they can be filled by horizontal dominoes. Number of ways of choosing the rows to place the vertical dominoes = 2 Number of ways of placing two vertical dominoes such that all three pieces of the row are even = number of solutions of the equation "a + b + c = 25". This is equal to 27 choose 2 = 351 Thus the required answer = 2 * 351 = 702
wow
that was cool
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