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Chemistry 11 Online
OpenStudy (anonymous):

Walk me through this? What would be the resulting molarity of a solution made by dissolving 25.4 grams of KOH in enough water to make a 985-milliliter solution? Show all of the work needed to solve this problem

OpenStudy (anonymous):

It is a strong base, so assume that it dissociates quantitatively. Find the number of moles of KOH. Once you have done that, divide the number of moles by the volume of the solution, expressed in litres. That will give you the molarity.

OpenStudy (anonymous):

How do I find the moles

OpenStudy (somy):

hmmm

OpenStudy (somy):

mole= mass/Mr

OpenStudy (somy):

u r given a mass of KOH and you can find Mr from periodic table

OpenStudy (anonymous):

the mass is 25.4 right?

OpenStudy (somy):

yes :)

OpenStudy (anonymous):

Okay so the moles is 0.453

OpenStudy (somy):

yupp

OpenStudy (anonymous):

Do I have to convert milliters to liters?

OpenStudy (somy):

yes :)

OpenStudy (anonymous):

0.985 liters

OpenStudy (anonymous):

So after I divided it I got 0.459

OpenStudy (somy):

so now what do u do next?

OpenStudy (anonymous):

There's more?

OpenStudy (somy):

yes

OpenStudy (somy):

molarity

OpenStudy (somy):

what is the formula?

OpenStudy (anonymous):

M = moles solute/liters solution

OpenStudy (somy):

so do it :)

OpenStudy (anonymous):

Okay so is the 0.459 the moles solute or the liters solution?

OpenStudy (somy):

wait

OpenStudy (somy):

its 0.453 moles

OpenStudy (somy):

volume is 0.985 L all as u said

OpenStudy (somy):

so molarity = mole/ volume

OpenStudy (anonymous):

0.459 is the answer i got

OpenStudy (somy):

oh lol u've become quite fast i didn't realize lol

OpenStudy (somy):

round to 0.460 M :D

OpenStudy (somy):

good jooob :D i see improvement <3

OpenStudy (anonymous):

Thank you:)

OpenStudy (somy):

u r welcome :D

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