Walk me through this?
What would be the resulting molarity of a solution made by dissolving 25.4 grams of KOH in enough water to make a 985-milliliter solution? Show all of the work needed to solve this problem
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OpenStudy (anonymous):
It is a strong base, so assume that it dissociates quantitatively.
Find the number of moles of KOH. Once you have done that, divide the number of moles by the volume of the solution, expressed in litres. That will give you the molarity.
OpenStudy (anonymous):
How do I find the moles
OpenStudy (somy):
hmmm
OpenStudy (somy):
mole= mass/Mr
OpenStudy (somy):
u r given a mass of KOH and you can find Mr from periodic table
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OpenStudy (anonymous):
the mass is 25.4 right?
OpenStudy (somy):
yes :)
OpenStudy (anonymous):
Okay so the moles is 0.453
OpenStudy (somy):
yupp
OpenStudy (anonymous):
Do I have to convert milliters to liters?
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OpenStudy (somy):
yes :)
OpenStudy (anonymous):
0.985 liters
OpenStudy (anonymous):
So after I divided it I got 0.459
OpenStudy (somy):
so now what do u do next?
OpenStudy (anonymous):
There's more?
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OpenStudy (somy):
yes
OpenStudy (somy):
molarity
OpenStudy (somy):
what is the formula?
OpenStudy (anonymous):
M = moles solute/liters solution
OpenStudy (somy):
so do it :)
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OpenStudy (anonymous):
Okay so is the 0.459 the moles solute or the liters solution?
OpenStudy (somy):
wait
OpenStudy (somy):
its 0.453 moles
OpenStudy (somy):
volume is 0.985 L
all as u said
OpenStudy (somy):
so molarity = mole/ volume
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OpenStudy (anonymous):
0.459 is the answer i got
OpenStudy (somy):
oh lol u've become quite fast i didn't realize lol
OpenStudy (somy):
round to 0.460 M :D
OpenStudy (somy):
good jooob :D i see improvement <3
OpenStudy (anonymous):
Thank you:)
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