Question

log 4 x + log 4 (x - 3) = 1

Answer 1

x = 1

Answer 2

\[\log4{x}+\log4{x-3} =1\]

Answer 3

x/(x+3) = 1/4
4x = x+3
x = 1

Answer 4

4 is base

Answer 5

suggestions: You might want to explain in words that these are "logs to the base 4", OR present your equation as a drawing (using the Draw utility, below). Also, please include the instructions with this problem.

Answer 6

A. x = 6 over 5
B. x = 2
C. x = -3
D. x = 4

Answer 7

\[ \log 4 x + \log 4 (x - 3) = 1\]

Answer 8

should be written as\[\log_{4}x+\log_{4}(x-3)=1 \]

Answer 9

... ok...

Answer 10

Since \[\log a + \log b = \log (a*b),\]

Answer 11

sox=4

Answer 12

or -1

Answer 13

\log_{4}x+\log_{4}(x-3)=1\[\log_{4}x+\log_{4}(x-3)=1~becomes~\log_{4}x(x-3)=1 \]

Answer 14

Note that we multiply x and (x-3); we do not divide. Know why?

Answer 15

I know

Answer 16

How would you now solve for x?

Answer 17

is log law

Answer 18

...x(x+3)=4

Answer 19

Good. What next?

Answer 20

x=1?

Answer 21

You can always check your own work by substituting your solution back into the original equation. If you believe x=1, then substitute that into \[\log_{4}x+\log_{4}(x-3)=1\]

Answer 22

and determine whether the resulting equation is true or not.

Answer 23

NVM I get it THANKS

Answer 24

If x=1, then log to the base 4 of (1-3) is undefined. Therefore, x=1 is not a solution.

You're welcome!